![求下列各三角函数值:(1)sin(-1920°)(2)cos(-1560°)(3)tan(-17π/6)-]()
1、求下列各三角函数值:(1)sin(-1920°)(2)cos(-1560°)(3)tan(-17π/6)-
答:[答案] sin(-1920°)=sin(-1920°+360°*6)=sin(240°)=-√3/2 cos(-1560°)=cos(-1560°+360°*5)=cos(240°)=-1/2 tan(-17π/6)=tan(-17π/6+π*3)=tan(1/6π)=√3/3
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答:[最佳答案] 前两个=round(A1/10000,1)计算结果应该是2.0. 最后一个=round(1560/1000,1)
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答:[最佳答案] 90+30=12090+45=13590+60=15060+45=10545+30=7590-30=6090-45=4590-60=3060-45=1560-30=3045-30=15
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